bash script help: escaping the '*'


 
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Top Forums Shell Programming and Scripting bash script help: escaping the '*'
# 15  
Old 10-07-2005
yes that works, but i want to test if the current word in $word variable in my original script is equal to the '*' character...
# 16  
Old 10-07-2005
Try this.

Code:
 
#! /bin/sh -f

for WORD in $(< input.txt)
do
        # Test only for *
        if [[ "${WORD}" == "*" ]] ; then
        echo "Only ${WORD}"
        # Test for a word containing characters along with a *
        elif [[ "${WORD}" == *"*"* ]] ; then
                echo "Contains * - ${WORD}"
        fi ;
done

From man sh

Code:
   Pathname Expansion
       After word splitting, unless the -f option has  been  set,  bash  scans
       each  word  for the characters *, ?, and [.  If one of these characters
       appears, then the word is regarded as a pattern, and replaced  with  an
       alphabetically  sorted  list of file names matching the pattern.


Vino
# 17  
Old 10-07-2005
its complaining about line 3...

Code:
./test: syntax error at line 3: `$' unexpected

# 18  
Old 10-07-2005
Replace the line

Code:
for WORD in $(< input.txt)

with

Code:
for WORD in `cat input.txt`

# 19  
Old 10-07-2005
so the -f option made the difference! thank God its works now..
ive been stuck on this problem the whole day!
you're a genius vino! Smilie Smilie Smilie many thanks!!!!
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