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Variable assignment inside awk

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# 8  
Old 04-11-2013
I have already given the way to read the values from array. Check the echo statement.

--ahamed
# 9  
Old 04-11-2013
I just Googled array usage and then realised that too - my mistake. Smilie

Although have I missed a | in the following:
Code:
root[my-box]# while read line; do 
val=(pntadm -P $line | awk '{if (( $2 == 00 && $1 != 00 ) || ( $2 == 04 )) print $3,$5}') 
echo ${val[0]} ${val[1]}; done < /tmp/final_list
bash: syntax error near unexpected token `|'
root[my-box]#

# 10  
Old 04-11-2013
I am not sure about the error, i think your OS is solaris - I see pntadm. Try using nawk.

--ahamed
# 11  
Old 04-11-2013
ok - thanks.

Back to my original question then - anyone know if there is a way to assign $3 and $5 to shell variables inside the {} brackets...

Thanks in advance
CiCa
# 12  
Old 04-11-2013
Did you try nawk?
Another way -
Code:
val=$( pntadm... )
ip=${val% *}
time=${val#* }

--ahamed
This User Gave Thanks to ahamed101 For This Post:
CiCa
# 13  
Old 04-11-2013
Ahh haa - it was the $ sign in val=$ that I needed...

This looks to be a good starting point to let me proceed with the rest of the script - thanks ahamed101.

Just out of curiosity, can you explain why you've put val% * and val#* in the following:
Code:
val=$( pntadm... )
ip=${val% *}
time=${val#* }

# 14  
Old 04-11-2013
They are shell string substitutions. The output from the pntadm statement results into IP address and Expiry date separated by space.

ip=${val% *} will remove everything from behind till it encounters a space i.e. it will remove the expiry date
time=${val#* } will remove everything from front till it encounters a space i.e. it will remove the IP address

--ahamed
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