awk to count start and end keyword in a line


 
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# 1  
Old 04-09-2013
awk to count start and end keyword in a line

Hello fellow awkers and seders:

need to figure out a way to ensure a software deployment has completed by checking its trace file in which I can store the deployment results as follows:

Code:
echo $testvar
===== Summary - Deploy Result - Start ===== ===== Summary - Deploy Result - End ===== ===== Summary - Deploy Result - Start ===== ===== Summary - Deploy Result - End ===== ===== Summary - Deploy Result - Start ===== ===== Summary - Deploy Result - End ===== <and so forth>

logic as follows:
- awk to look for keyword=Start; if found, then look for the keyword=End
- when we have the sequence: Start|End|Start # this indicates deployment is in progress or stuck
- every "Start" keyword has to pair with a subsequent "End" keyword

Would greatly appreciate it if anyone out there can help me crack this brain teaser Smilie

Thanks.
# 2  
Old 04-09-2013
Assuming your input exactly looks like the example you provided :

Code:
echo $test | awk -F"= =" 'NF%2{print "Deploymeny still in progress"}'

This User Gave Thanks to ctsgnb For This Post:
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