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Shell Programming and Scripting

Delete if condition met in a column

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Top Forums Shell Programming and Scripting Delete if condition met in a column
# 8  
Old 04-08-2013
Thanks PikK45,

using this:

Code:
BLOCKLIST="$( mysql -uroot -pabcde smsd -N -s -r -e "SELECT senderNumber FROM blacklist WHERE senderBlock='Y'" | sed 's/^0/+61/g' | tr '\n' ',' | sed 's/,$//g' )"
mysql -uroot -pabcde smsd -e "DELETE FROM inbox WHERE senderNumber = '$BLOCKLIST'"



output:

Code:
sh -x /etc/autodelete.sh
+ tr \n ,
+ sed s/,$//g
+ sed s/^0/+61/g
+ mysql -uroot -pabcde smsd -N -s -r -e SELECT senderNumber FROM blacklist WHERE senderBlock='Y'
+ BLOCKLIST=+6183808034690,+618164853500
+ mysql -uroot -pabcde smsd -e DELETE FROM inbox WHERE senderNumber = '+6183808034690,+618164853500'

but still the record not deleted.
# 9  
Old 04-08-2013
Dear jazzyzha,

I missed to add IN there.
Code:
mysql -uroot -pabcde smsd -e "DELETE FROM inbox WHERE senderNumber = '$BLOCKLIST'"

should be changed to
Code:
mysql -uroot -pabcde smsd -e "DELETE FROM inbox WHERE senderNumber IN ('$BLOCKLIST')"

This User Gave Thanks to PikK45 For This Post:
jazzyzha
# 10  
Old 04-08-2013
Thank you Brother PikK45 !, now it can delete the new record. :-D thank you so much for your help.
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