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awk print variable then fields in variable

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# 1  
Old 04-06-2013
awk print variable then fields in variable
i have this variable:

Code:
varT="1--2--3--5"

i want to use awk to print field 3 from this variable. i dont want to do the "echo $varT".

but here's my awk code:
Code:
awk -v valA="$varT" "BEGIN {print valA}"

this prints the entire line. i feel like i'm so close to getting what i want. i basically just want to fork another awk process or any other command.

i was thinking this would work, but it didn't:

Code:
awk -v valA="$varT" "BEGIN {print valA,$3}"

# 2  
Old 04-06-2013
If you want to do it that way you could try:
Code:
awk -v valA="$varT" 'BEGIN{split(valA,F,/--/);print F[3]}'

This User Gave Thanks to Scrutinizer For This Post:
SkySmart
# 3  
Old 04-06-2013
Quote:
Originally Posted by Scrutinizer
If you want to do it that way you could try:
Code:
awk -v valA="$varT" 'BEGIN{split(valA,F,/--/);print F[3]}'

this worked perfectly. can i print the last field using this command? i tried:

Code:
awk -v valA="$varT" 'BEGIN{split(valA,F,/--/);print F[NF]}'

but i didn't get anything.
# 4  
Old 04-06-2013
Try:
Code:
awk -v valA="$varT" 'BEGIN {n=split(valA,F,/--/); print F[n]}'

This User Gave Thanks to Scrutinizer For This Post:
SkySmart
# 5  
Old 04-06-2013
AWK split function returns the number of elements created:
Code:
awk -v valA="$varT" 'BEGIN{n=split(valA,F,/--/);print F[n]}'

This User Gave Thanks to Yoda For This Post:
SkySmart
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