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Shell Programming and Scripting

Time condition exit loop

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# 1  
Old 04-01-2013
Time condition exit loop
Hi All,

Requirement: The below script should automatically exit at 6pm everyday without manually killing the script

Tried running with the below shell script but found the script was still running when the time was 6:15pm. The script did not exit the while loop at 6pm

The script runs thorugh cron at 9AM Mon-Fri

Code:
Script xyz.sh

#!/bin/bash

hr=$(date +"%H")
while [ $hr -ge 9 -a $hr -lt 18 ]; do
some task is performed...
done

Thanks for your time!

Regards,
a1_win
Last edited by Corona688; 04-02-2013 at 02:42 PM..
# 2  
Old 04-02-2013
Try this:
Code:
hr=$(date +"%H")
while [ $hr -ge 9 -a $hr -lt 18 ]
do
  some task is performed...
  sleep 5 # 5 secs; So you don't have a tight loop
  hr=$(date +"%H")
done

# 3  
Old 04-02-2013
Hi Spacebar,

Thanks but this is not working!

Tried executing with the below command but it exited without running anything..

Code:
hr=$(date +"%H")
while [ $hr -ge 22 -a $hr -lt 01 ] # For example,tried time range between 22hrs and 01 AM as test 
do
   do some task....
  sleep 5 
  hr=$(date +"%H")
done

output:

Code:
-bash-3.2$ ./xyz.sh &
[1] 30061
-bash-3.2$
[1]+  Done                    ./xyz.sh
-bash-3.2$

Any other suggestion?


a1_win
# 4  
Old 04-02-2013
Quote:
Originally Posted by a1_win
Hi Spacebar,

Thanks but this is not working!

Tried executing with the below command but it exited without running anything..

Code:
hr=$(date +"%H")
while [ $hr -ge 22 -a $hr -lt 01 ] # For example,tried time range between 22hrs and 01 AM as test 
do
   do some task....
  sleep 5 
  hr=$(date +"%H")
done

output:

Code:
-bash-3.2$ ./xyz.sh &
[1] 30061
-bash-3.2$
[1]+  Done                    ./xyz.sh
-bash-3.2$

Any other suggestion?


a1_win
# 5  
Old 04-02-2013
There is no number that is greater or equal than 22 and at the same time lower than 1.
Code:
hr=$(date +"%H")
while [ $hr -ge 22 -o $hr -lt 01 ] # For example,tried time range between 22hrs and 01 AM as test 
do
   do some task....
  sleep 5 
  hr=$(date +"%H")
done

# 6  
Old 04-02-2013
Linux Time script
Hi a1_win,

Below script will execute in infinite while loop. When current time (cur_time) reaches script kill time (kill_time) it will exit the script.
Code:
#!/bin/bash

kill_time=1800
while true
do
          cur_time=`date "+%H%M"`
          if [ $cur_time -gt $kill_time ]; then
                    exit 5           # To find exit status of the script
          fi
          echo "Hello World"
          sleep 60                 # To execute script every 1 minute
done

Last edited by Franklin52; 04-02-2013 at 08:44 AM.. Reason: Please use code tags
# 7  
Old 04-02-2013
Quote:
Originally Posted by a1_win
Thanks but this is not working!
Tried executing with the below command but it exited without running anything..
Code:
hr=$(date +"%H")
while [ $hr -ge 22 -a $hr -lt 01 ] # For example,tried time range between 22hrs and 01 AM as test 
do
   do some task....
  sleep 5 
  hr=$(date +"%H")
done

The script doesn't understand "time" it is just seeing integers, so make sure your comparison numerical wise is valid.
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