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# 1  
Old 03-30-2013
Print at same line
Hello

I am trying to write a shell script. I want the script to repeat at the same line e.g. 12 times the word "foo".

like
Code:
foo foo foo foo foo foo foo foo foo foo foo foo

so i would like to input the program how many times i want this word to be repeated.

Is it possible?

(I am new to this!!!)
Last edited by Scrutinizer; 03-30-2013 at 05:28 AM.. Reason: code tags
# 2  
Old 03-30-2013
You can try this

Code:
echo "foo" | awk '{for(i=1;i<=12;i++)printf "%s\t", $1; printf "\n"}'

resulting

Code:
foo    foo    foo    foo    foo    foo    foo    foo    foo    foo    foo    foo

This User Gave Thanks to Akshay Hegde For This Post:
lengolass
# 3  
Old 03-30-2013
thanks

---------- Post updated at 02:14 AM ---------- Previous update was at 01:58 AM ----------

in this command
Code:
echo "foo" | awk '{for(i=1;i<=12;i++)printf "%s\t", $1; printf "\n"}'

can i change the number 12 with a variable??

like

Code:
atoms=$1
echo "foo" | awk '{for(i=1;i<=$atoms;i++)printf "%s\t", $1; printf "\n"}'

is this possible?

I wrote it but It doesnt work
Last edited by Scrutinizer; 03-30-2013 at 04:55 AM.. Reason: code tags
# 4  
Old 03-30-2013
try this
Code:
atoms=1
echo "foo" | awk '{for(i=1;i<='$atoms';i++)printf "%s\t",$1;printf "\n"}'

# 5  
Old 03-30-2013
Why use an external program. With bash/ksh93:
Code:
n=12; for (( i=1; i<=n; i++ )); do printf "%s " "foo"; done; echo

Code:
n=12
for (( i=1; i<=n; i++ ));do
  printf "%s " "foo"
done
echo

or any POSIX shell (including bash/ksh93):
Code:
n=12 i=$n
while [ $((i-=1)) -ge 0 ]; do
  printf "%s " "foo"
done
echo

Last edited by Scrutinizer; 03-30-2013 at 06:03 AM..
# 6  
Old 03-30-2013
Or use printf alone:
Code:
printf "foo%.0s " {1..12}; printf "\n"

Reading from a file:
Code:
n=12
while read line; do
        printf "${line}%.0s " $(seq 1 $n); printf "\n"
done < file

# 7  
Old 03-30-2013
Hi.
Code:
% jot -b foo -s " " 10 1
foo foo foo foo foo foo foo foo foo foo

Best wishes ... cheers, drl
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