10 More Discussions You Might Find Interesting
1. HP-UX
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
2. HP-UX
HI,
Can anyone tell me how to pull the date and file name separated by a space using the find command or any other command. I want to look through several directories and based on a date timeframe (find -mtime -7), output the file name (without the path) and the date(in format mmddyyyy) to a... (2 Replies)
Discussion started by: lnemitz
2 Replies
3. Shell Programming and Scripting
Hi all,
Need an urgent help on the below scenario.
script:
awk -F","
'BEGIN { #some variable assignment}
{ #some calculation and put values in array}
END {
year=#getting it from array and assume this will be 2014
month=#getting it from array and this will be 05
date=#... (7 Replies)
Discussion started by: vijaidhas
7 Replies
4. UNIX for Dummies Questions & Answers
I need to generate a report on the first of each month that will show me how many points are going to expire on a particular scheme for the next three months. The points expiry is not an issue what I have an issue with is finding the command to give me the last day of each month for the current and... (2 Replies)
Discussion started by: theref
2 Replies
5. Shell Programming and Scripting
Hi,
does anybody know how to format `date` command correctly to return the day of the week? Thanks -A
I work in ksh.... (1 Reply)
Discussion started by: aoussenko
1 Replies
6. Shell Programming and Scripting
When I write
Select date_field from TableA fetch first row only
I am getting the output as 09/25/2009.
I want to get the output in the below format
2009-09-25 i.e., MM-DD-YYYY. Please help (7 Replies)
Discussion started by: dinesh1985
7 Replies
7. Shell Programming and Scripting
Hi,
I wrote a simple shell script which accepts the input value yearmonth in the format YYYYMM and displays the date as YYYY-MM-DD.Day will be 01 always.Please find the code below
#!/bin/ksh
export yearmonth_date=$1
print_usage() {
echo "usage: ${0##*/} <yearmonth_date> \n" \
... (1 Reply)
Discussion started by: kavithakuttyk
1 Replies
8. Shell Programming and Scripting
Hi
Do you have any pointers how to validate numbers (not to contain alphabets and special characters) and date(MM/DD/YYYY) format.
I used following regular expression to validate integer, which is not working in the default shell:
nodigits="$(echo $testvalue | sed 's/]//g')"
... (4 Replies)
Discussion started by: alok_jax
4 Replies
9. UNIX for Dummies Questions & Answers
Good day folks,
This is my first post on this board and I thank you in advance for helping me with this issue.
Any idea how I can synchronize server time with another timeserver but have my server lag behind by 2 seconds?
Meaning...I need a simple unix script that I can run as crone that... (2 Replies)
Discussion started by: franklo
2 Replies
10. UNIX for Advanced & Expert Users
Hi there,
I am trying to do the following in Unix (Solaris 2.7):
1...Find the actual date 7 days ago in format (dd-mmm-yyyy) and with the weekday prefably,
2...Find the date 5 days after the above in the same format.
How can I do this in Unix instead of accessing our Oracle database and... (5 Replies)
Discussion started by: csong2
5 Replies