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Shell scripting- cut the location of the file

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# 1  
Old 03-18-2013
Blade Shell scripting- cut the location of the file
Hi,

I need to just cut the location of file and give it as input to the other command. For example:
Code:
ct lsview | grep kavya-
* kavya-telecom-view   /first/nso01/disk2/views/kavya-telecom-view.vws

I need only the location like /first/nso01/disk2/views/kavya-telecom-view.vws.How to cut that part.

Thanks to help.
Last edited by Franklin52; 03-18-2013 at 07:57 AM.. Reason: Please use code tags for data and code samples
# 2  
Old 03-18-2013
Pls use code tags as required by forum rules!

Code:
$ ct lsview | awk '/kavya-/ {print $3}'
/first/nso01/disk2/views/kavya-telecom-view.vws

or
Code:
$ ct lsview | grep kavya- | cut -d" " -f3

Reading man pages or searching these fora sometimes really helps!
# 3  
Old 03-18-2013
Hi thanks for the reply.

But 2nd one it is shoeing invaild delimiter. And if possible can you explain the 1st one???
# 4  
Old 03-18-2013
awk '/kavya-/ -- > If your input line contains "Kavya-" in it , {print $3}' ---> print the third field ..Default delimiter is space here.
# 5  
Old 03-18-2013
"Invalid delimiter" would be very surprising unless you have a typo when copying the command.
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