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If statement test against number range [0-9]

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# 1  
Old 03-13-2013
If statement test against number range [0-9]
Is it possible to test against a varible within a ranges in a if statement.

ex.
Code:
 if [ $test != [0-9] ];then
echo "not in range"
else
echo "number within range"
f

i
Last edited by vbe; 03-13-2013 at 01:34 PM..
# 2  
Old 03-13-2013
read about the relational operators and boolean operators in shell ( google it )
This User Gave Thanks to itkamaraj For This Post:
leemalloy
# 3  
Old 03-13-2013
Hi, is this what you need?
Code:
if [[ $test -ge $LOWER ]] && [[ $test -le $UPPER ]]; then echo "in range"; else echo "not in range"; fi

# 4  
Old 03-13-2013
@franzpizzo: if LOWER is less or equal 0, and test is alpha, it will be considered "in range"!
This User Gave Thanks to RudiC For This Post:
leemalloy
# 5  
Old 03-13-2013
@RudiC
Hi, queston is: the request is a validation check or only a check for the range?
This check have not sense for alphanumeric value of test variable.
Thanks
This User Gave Thanks to franzpizzo For This Post:
leemalloy
# 6  
Old 03-13-2013
I'm using it to validate a numer range because it a number is chose outside of the range I and exiting the program
# 7  
Old 03-13-2013
You were pretty close with your original code, just use double [ and ] :

Code:
if [[ "$test" != [0-9] ]];then
   echo "not in range"
else
   echo "number within range"
fi

This User Gave Thanks to Chubler_XL For This Post:
leemalloy
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