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awk return number of entries

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# 1  
Old 03-06-2013
awk return number of entries
I have a string with the following information and want to return the number of entries enclosed by <> in awk



Code:
<stdin>: N = 441    <0.369000018/0.569000006>    <0.369000018/0.569000006>    <0/1>

# 2  
Old 03-06-2013
Try:
Code:
awk '{print gsub(/<[^>]*>/,x)}'

# 3  
Old 03-06-2013
The variable is in a bash script

Code:
x="<stdin>: N = 441    <0.369000018/0.569000006>    <0.369000018/0.569000006>    <0/1>"

And need to pass it to awk somehow, possibly using -v

Code:
s="<stdin>: N = 441    <0.369000018/0.569000006>    <0.369000018/0.569000006>    <0/1>"
awk -v x="$s" '{print gsub(/<[^>]*>/,x)}'

The command stalls giving me 0 all the time when I press return
Last edited by kristinu; 03-06-2013 at 01:27 PM..
# 4  
Old 03-06-2013
The awk program stalls because it is expecting input. Use echo instead:
Code:
echo "$s" | awk '{print gsub(/<[^>]*>/,x)}'

---------- Post updated at 11:46 ---------- Previous update was at 11:33 ----------

OR use a BEGIN block:
Code:
awk -v x="$s" 'BEGIN{print gsub(/<[^>]*>/,X,x)}'

# 5  
Old 03-06-2013
Thanks a lot. It would be good to explain how the number the calculated with that command as I am not getting it. It works though.

I tried the following, incrementing i which also works

Code:
echo "$s" | awk '{print gsub(/<[^>]*>/,++i)}'

Last edited by kristinu; 03-06-2013 at 01:55 PM..
# 6  
Old 03-06-2013
Regexp /<[^>]*>/ means:

/ -- Begin pattern

<[^>]*> -- < followed by zero or more occurrence * of any character [^>] other than > followed by >

/ -- End pattern

The gsub function returns the number of substitutions made which the code prints.
These 2 Users Gave Thanks to Yoda For This Post:
kristinu Scrutinizer
# 7  
Old 03-06-2013
Got it, so in principle I can replace x with "" as it is just a replacement. Is that correct?
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