Shell Programming and Scripting

Hi,
Maybe a biggy but I want to make it clear what i'm trying to achieve......

I'm a big stuck and need a bit of a pointer. I'm not sure how to explain this.

My input file follows the format below. When I read the file each time I get a ~FILE? I want to assign it to var1 then each num/value that is comma seperated will be assigned to var2 and used to execute a diff comamnd/script.

Example: script ~FILE1 1
script ~FILE1 2


File format. (lines beginning with comma , are continuation of previous line and are new line seperated after 7 entries, numbers will never follow a sequence like in this example)
~FILE1,1,2,3,4,5,6,7
,8,9
~FILE2,1a,2a,3a
~FILE3,1b,2b,3b,4b,5b,6b,7b
,8b,9b,10b,11b

Once a get to the next ~FILE? that becomes var1 and subsequent , comma speerated fields become var2 and are used on the same script.

Example: script ~FILE2 1a


How can I read the line and seperate each in the way that I want? I have played around with read and shift and a few other no hopers to achive nothing. I end up with var1 and var2 being the same string I get no strings assigned to either var.

Any help will be great.....


Cheers and beers to the winner....

Only joking on the beer...unless winner collects....

You don't say which shell you are using. This is bash but might work for ksh...

Code:

while read line
do
    IFS=','
    eval set $line
    if [[ $1 == ~* ]]
    then
        param1=$1
        shift
    fi
    while [[ $# -gt 0 ]]
    do
        echo script $param1 $1
        shift
    done
done < filein

The result is...

Code:

script ~FILE1 1
script ~FILE1 2
script ~FILE1 3
script ~FILE1 4
script ~FILE1 5
script ~FILE1 6
script ~FILE1 7
script ~FILE1 8
script ~FILE1 9
script ~FILE2 1a
script ~FILE2 2a
script ~FILE2 3a
script ~FILE3 1b
script ~FILE3 2b
: