Shell Programming and Scripting

Hello Gurus,

I've searched enough to find what I wanted and finally ended up creating a thread.
I'm in the process of coding something like below

sed -n -e "s/.*\(successfully completed\).*/\1/p" xxx.log
read status
if [[ "$status" = successfully completed ]]
then
#sleep 3;
echo "Export successful and exiting"
else
Send the log file as attachment
/usr/sbin/sendmail -f "expdp error" name@email.com << END
subject: Expdp error log
`cat <path>/body-message.txt`
`uuencode xxxx.log xxxx.log`
END
fi

I've an issue in string comparison as the condition is not being met in "if " condition, and always sends me an email (that's satisfying the else condition)

Can some one please help.

Please use code tags when posting code.

Why do you expect variable "status" to hold anything from the sed command? Assign to it from the sed command and skip the 'read'.
You can always 'echo' variable to see what it holds.

Code:

status=$(sed -n -e "s/.*\(successfully completed\).*/\1/p" xxx.log)
echo status $status
if [[ "$status" = "successfully completed" ]]
...

Along with mirni's change, you have to add quotes

Code:

if [[ "$status" = "successfully completed" ]]

what you get when you manually execute

Code:

sed -n -e "s/.*\(successfully completed\).*/\1/p" xxx.log

---------- Post updated at 01:15 PM ---------- Previous update was at 01:13 PM ----------

shouldn't be "==" rather than "=" ?

Thank you guys!

Mirin's suggestion helped me, when I used
status=$(sed -n -e "s/.*\(successfully completed\).*/\1/p" xxx.log)

"status=$" - this infact made the change.
I was thinking that the output "successfully completed" is being read and displayed from the "status", variable. I in fact, commented out all until sed and the program execution still displayed "successfully completed". so that narrated the story for me.

Thank you very much for all your help.