Shell Programming and Scripting

One way might be:

Code:

awk '{$1=$1; sub($1 FS $2 FS,x)}1' RS= file

But only if the empty lines are completely empty (contain no whitespace).

Thanks for the reply. I am not sure if empty lines will be completely empty, can we do one thing if that does not need any kind of assumption...I am fine closing the data in the end with ";", so is there anyway we can get the string which starts with "=" and ends with ";".
Your solution again getting me the all lines of file in one go...requesting to please let me know if i can get one by one as explained in the post. Once again thanks for spending time on this on helping me.

---------- Post updated at 06:01 AM ---------- Previous update was at 05:34 AM ----------

Also please note that it is not a fixed length file that means the number of words are not fixed...

One thing that is not clear is, where does the script get the information that "C" files need an extension ".c" and C++ files need ".cpp" etc..

that information will not come from anywhere...once i am able to extract the strings...then i need to write function which will check for validation...but in 1st place i dont know how to extract the string...I hope I am clear...do we have any instr oracle like command in Unix..if something like that is there...then i can simple get the position of ";" and then from there i can get substring using substr...Any advice please..

Perhaps something like this is more what you are looking for:

Code:

#!/bin/bash
while read -a line
do
  if [[ ${line[1]} == "=" ]]; then
    ptype=${line[0]}
    unset line[0] line[1]
  fi
  for file in "${line[@]}"
  do
    echo "Check if \"$file\" belongs to type \"$ptype\""
  done
done < infile

Thank You...This is what i was looking for. If possible could you please confirm the following points:line[1] does it mean, "=" operator in my file has to be 2nd word in each line without any space.

Yes, that is correct.