Your awk program were working fine if you searched for the end of $3, represented by "$", instead of looking for whitespace which, being the field separator, was stripped off:
Hello,
Im looking to help out my team by automating a simple search list. The user will look for a peering ip /30. For example 192.168.1.2/30 and gets the result. Im trying to get the entered /30 and subtract the last octet by one.
echo -n "Enter peering ip : "; read peeringip
cat... (3 Replies)
Hi Experts,
I am trying to print $2 & the IP_address upto 3rd octet only.
But unable to do so, Trying # awk '{print $2, substr($4,1,9)}' file . but not correct
File:
HOST= cmiHOST06 :: 10.26.107.73:/data120 /nbu/cmiHOST06/athpx07/aa1
HOST= cmiHOST05 :: 10.26.12.76:/data120... (5 Replies)
I'm trying to learn as much about GRUB as I can and it's stages are stored in these types of files.
Any info or search terms is appreciated!:wall: (5 Replies)
Hi All,
I found my weblog contain entries like 121.23.3 Instead of four octet.
I am quite confused is it possible to have 3 octet ip at all ??
Is it generating by any program and hittng the website ?
Is it a subdomain ?
Please tell me your understanding on it ?
Thanks (4 Replies)
Hi all,
Situation is as below.
I would get an IP address and port from eithe r a file or command line. It probably would be as char * or string. So was wondering how I could accept this and increment the last octets?
Incrementing the port is fine. I could get that into an integer by atoi()... (8 Replies)