Shell Programming and Scripting

Hi Everyone,

I have a question:
I have a lot of file named like
or10000.dat, or9100.dat, or100.dat, or3100.dat...
I want to deal with these files according to the
number in the name. So I want to deal with or100.dat
first and then or3100.dat and so on.

I used :

Code:

for i in `ls or*.dat | sort -n`;do ...

but the first one is or 10000.dat.

Is there an easy way to do that?
Thanks in advance!

/YC

Use sort -k through which you can specify the starting and ending position of your sort criteria.

So in your case

Code:

ls or*.dat | sort -k2 -n

---------- Post updated at 03:50 AM ---------- Previous update was at 03:48 AM ----------

Sorry..It should be -k3

try:

Code:

for i in `ls or*.dat | sort -k1.3n`;do

Some sorts allow a --debug option which is good to see what they are sorting on.

Thank you. I tried that. but the file of or10000.dat is still
in front of or100.dat.
it seems not to work.

Yes my solution should work

Yes Chubler_XL is correct..should use 'k.'

Code:

ls or*.dat | sort -t' ' -k1.3 -n
or100.dat
or9100.dat
or10000.dat

Moderator's Comments:

Please use code tags next time for your code and data.

Yes, this one works. But I don't know why even after I read
the man page of sort. There is no "-k.". Would you please
explain why this one works? thank you.

by the way I tried to use --debug, but I got unrecognized option '--debug'