Shell Programming and Scripting

Code:

[root@ds-accm-z2-pri196 ~]# date +%s -d "Mon Feb 11 02:26:04"
1360567564
[root@ds-accm-z2-pri196 ~]# perl -e 'print scalar localtime(1360567564), "\n";'
Mon Feb 11 02:26:04 2013

the epoch conversion is working fine. but one of my application needs 13 digit epoch time as input

Code:

1359453135154

rather than 10 digit epoch time

Code:

1360567564

is there some conversion that i am missing? any help will be deeply appreciated. thanks

PS: in one of the epoch online conversion website i tried to convert both types of epoch time. both are working but in unix i am not able to convert into 13 digit output epoch time :-(

Code:

Code:

http://www.epochconverter.com/

epoch 13 uses milliseconds instead of seconds, since you are not using the extra precision with your date command, why not try simply adding 3 zeroes at the end?

Code:

date +%s000 -d "Mon Feb 11 02:26:04"

thanks mate it worked with my application :-)

Hi all,
Can any1 suggest me how can i get the epoch time of file.
i mean...
ls -l test.txt | awk '{print $6,""$7,""$8}' gives me Nov 30 2011...
now is there any way i can convert this into epoch time for this particular file only...
Thanks