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Grep words with spaces and save the output

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# 1  
Old 02-08-2013
Grep words with spaces and save the output
I have a file that contains the schedule for a tournament with 41 teams. The team names have spaces in them. I would like to search for each teams schedule and then save that to that teams file

For example

Team name: "Team Two"

I would like to search for all the games for "Team Two" and then the result I would like to save it to a file called Team_Two

All the teams names are in a file called Teams and few of the team names have spaces in them

Code:
TeamOne
Team Two
Team Three
TeamFour
Team Five O
Team Six
Team Seven

and so on ..

Team Forty one.


Code:
$ for i in `cat teams`
do
grep -i "$i" schedule >> $i (how do I replace the space before saving it)
done

The output I would like to expect is Each teams schedule saved in their team name

This is not really urgent but can someone please help me out
Last edited by Scrutinizer; 02-08-2013 at 05:37 PM.. Reason: code tags
# 2  
Old 02-08-2013
Code:
while read i
do
i2=$( echo "$i" | tr ' ' '_' )
grep -i "$i" schedule >> "$i2"
done < teams

Last edited by DGPickett; 02-11-2013 at 10:25 AM.. Reason: Change spaces in file name to _
# 3  
Old 02-11-2013
this still saves the team names with spaces.
I want to save the file without the space.

for example when I grep the schedule for "Team Two" from the schedule file it should have the content of Team Two schedule in the file named Team_Two
# 4  
Old 02-11-2013
Something like this?

cat data
Code:
TeamOne
Team Two
Team Three
TeamFour
Team Five O
Team Six
Team Seven
Team Forty one.

Code:
awk -F"Team[ ]*" '{print "Team_"$2}' data > result

cat result
Code:
Team_One
Team_Two
Team_Three
Team_Four
Team_Five O
Team_Six
Team_Seven
Team_Forty one.

Using the Field Separator like "Team[ ]*", will give correct split.
Last edited by Jotne; 02-11-2013 at 02:54 AM..
# 5  
Old 02-11-2013
Bash / ksh93 / zsh
Code:
while read i
do
  grep -i "$i" schedule >> "${i// /_}"
done < teams

# 6  
Old 02-11-2013
Code:
$ while read i
> do
> grep -i "$i" schedule >> "${i// /_}"
> done < teams
/usr/bin/ksh[3]: "${i// /_}": bad substitution
/usr/bin/ksh[3]: "${i// /_}": bad substitution
/usr/bin/ksh[3]: "${i// /_}": bad substitution
/usr/bin/ksh[3]: "${i// /_}": bad substitution
/usr/bin/ksh[3]: "${i// /_}": bad substitution
/usr/bin/ksh[3]: "${i// /_}": bad substitution
/usr/bin/ksh[3]: "${i// /_}": bad substitution

---------- Post updated at 07:21 AM ---------- Previous update was at 07:11 AM ----------

Thank you so much. it worked. I didnt realize you asked me to use any of the following shells
Bash / ksh93 / zsh
I used zsh and it worked.
Last edited by Scrutinizer; 02-11-2013 at 07:24 AM.. Reason: code tags
# 7  
Old 02-11-2013
Good. With other shells you could try the less efficient "$(echo "$i" | tr ' ' '_')" instead of "${i// /_}"
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