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Shell Programming and Scripting

Extracting entries starting with xxx

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# 1  
Old 02-07-2013
Extracting entries starting with xxx
Hello,
I am trying to extract all words (entries) from a file beginning with 123. For example:

Code:
ververv ewfaafa 123asd 4334j fdgfgf
fdfdssd 123890 xxxxx eeee sss 1234 sdfsf were sfs fbdsdfb
fsdg sdgfsd bfg sdfb dsfb 
sdfg sdf ergerg 123pop sdfgdfg 123ww 123qq dffg

Desired output:
Code:
123asd
123890
1234
123pop
123ww
123qq

Thanks so much!
Last edited by Scrutinizer; 02-07-2013 at 09:04 PM.. Reason: code tags
# 2  
Old 02-07-2013
Code:
awk '{ for(i=1;i<=NF;i++) if($i ~ /^123/) print $i; }' file

This User Gave Thanks to Yoda For This Post:
palex
# 3  
Old 02-07-2013
Just to provide an alternative, assuming that your words are space-separated:

Code:
tr ' ' '\n' < yourfile | grep ^123

# 4  
Old 02-07-2013
Or if you have GNU grep:
Code:
grep -o '123[a-zA-Z0-9]*' file

EDIT: My bad, please ignore this post. Thanks Scrutinizer for pointing that out.
Last edited by Yoda; 02-07-2013 at 09:15 PM.. Reason: My bad, please ignore this post. Thanks Scrutinizer for pointing that out.
# 5  
Old 02-07-2013
The latter command would also print when 123 is not the start of a word, for example:
Code:
$ echo 4123x | grep -o '123[a-zA-Z0-9]*'
123x

This User Gave Thanks to Scrutinizer For This Post:
Yoda
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