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Grep awk sed display value

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# 1  
Old 02-06-2013
Grep awk sed display value
Hello all,

I wget a file and i tried to display some value :

Code:
content=$(wget IP:9005/GlobalStatistics -q -O -) 
echo onlineusers $content > /home/active_session_log

#cat active_session_log 

{"ActiveSessionCount":0,"ActiveGameCount":0,"QueueMatchMakingPlayerCount":0}

My goal is write log file with ActiveSessionCount and the value

Exemple :
Code:
#cat ActiveSessionCount.log 
ActiveSessionCount 0

Any idea?
Last edited by joeyg; 02-06-2013 at 01:21 PM.. Reason: Please wrap commands and data with CodeTags
# 2  
Old 02-06-2013
Code:
awk -F'[:|,]' '/ActiveSessionCount/{ gsub(/\"|\{/,x,$1); print $1, $2 } ' active_session_log

# 3  
Old 02-06-2013
Code:
awk -F'[":,]' '{print $2,$4}' active_session_log > ActiveSessionCount.log

@bipinajith
I think you do some wrong in your field separator
You can do this -F'[:,]' or this -F':|,'
This -F'[:|,]' gives : | , as separators
This User Gave Thanks to Jotne For This Post:
Yoda
# 4  
Old 02-06-2013
ok great :P
Code:
awk -F'[:,]' '/ActiveGameCount/{ gsub(/\"|\{/,x,$1); print $1, $2 } ' active_session_log
ActiveSessionCount 0

and now if i would like grap the other value ?
Last edited by radoulov; 02-06-2013 at 03:23 PM..
# 5  
Old 02-06-2013
How would you like to output? to different files?
And please use code tags
# 6  
Old 02-06-2013
Yes to different files !
# 7  
Old 02-06-2013
Code:
awk -F'[":,]' '{print $6,$8}' active_session_log > ActiveGameCount.log
awk -F'[":,}]' '{print $10,$12}' active_session_log > QueueMatchMakingPlayerCount.log

---------- Post updated at 20:20 ---------- Previous update was at 20:09 ----------

All in one go
Code:
awk -F'[":,}]' '{print $2,$4 > $2".log"; print $6,$8 > $6".log" ;print $10,$12 > $10".log"}' active_session_log
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