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need help in Grep a string in the log file

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# 1  
Old 02-05-2013
need help in Grep a string in the log file
Code:
logfile="/var/tmp.log"
output=$(grep "ERROR" $logfile)
if [ -n $output ]
then
    echo "exceptions logged , please check /var/tmp.log for more details" |\
   mail -s "exceptions logged , please check /var/tmp.log on  for more details" $DL
else
    echo "not found"
fi

Somehow its not working as expected, I am trying to grep the error string and send an email if the string "error" is present on the log file, could you please help in this?
Last edited by vbe; 02-05-2013 at 12:00 PM..
# 2  
Old 02-05-2013
What is not working?
We cant really help you based on what you gave us so far...
Did you get an error in your script?
What is the content of $output? etc....
# 3  
Old 02-05-2013
thanks for the quick reply
Code:
: [: too many arguments
+ echo 'not found'
not found

The issue is if [ -n $output ] getting as "too many arguments"

When i try to run the script, It was able to find the "error" (saying too many arguments) and finally its says not found, even though the log file has the matches strings
Last edited by Franklin52; 02-06-2013 at 06:19 AM.. Reason: Please use code tags for data and code samples
# 4  
Old 02-05-2013
Hi
try to enclose the variable with double quotes:

if [ -n "$output" ]
....Smilie
This User Gave Thanks to franzpizzo For This Post:
ajothi
# 5  
Old 02-05-2013
Or try:
Code:
logfile="/var/tmp.log"
if grep -q "ERROR" "$logfile"
then
        echo "Exceptions logged, please check ${logfile} for more details" | mail -s "Exceptions logged" $DL
else
        echo "Not found"
fi

This User Gave Thanks to Yoda For This Post:
ajothi
# 6  
Old 02-05-2013
Thank you both!!
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