Shell Programming and Scripting

Hi

can someone help me in writing a Ksh script to get the line between two characters

Problem:
I have a file which has data as below

abcd :
some line
some line
some line
some line

1234 :
some line
some line
some line
some line


ABCD :
some line
some line
some line
some line

etc ...


I need to write a script to get the lines between ":" and ":"




Thanks in Advance


:

If you mean all lines that do not have a colon -

Code:

grep -v ":" filename

Thanks Jim ;

I am not looking for that:

I am looking for a solution for as follows

If I pass

1234

it has to get me


some line
some line
some line
some line


ABCD

nawk -v id='1234' -f srini.awk my File

srini.awk:

Code:

BEGIN {
  FS=RS=""
  OFS="\n"
}
$1 ~ ("^" id " *:$") {$1=""; print }

Code:

BEGIN { RS = ":" ; ARGC-- }
f-- > 0
ARGV[2] == $NF { f = 1 }

awk -f get.awk datafile '1234'

I stand corrected.
Very nice, futurelet!!!!

Thanks, vlad, but I wasn't trying to correct you. I assumed that your code was correct. When a lazier solution occurs to me, I can't resist posting it.