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Unexpected EOF while looking for matching `'' when ran from a cron job

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# 1  
Old 02-04-2013
Unexpected EOF while looking for matching `'' when ran from a cron job
Since cPanel does not support deleting emails older then X amount of days I am using the following on a Cron Job.

Code:
find -P /home/user/mail/domain/ -mindepth 2 -mtime '+366' -type f -printf '"%p"\n' | grep -v '/Important' | grep -v '/.Important' | xargs -I {} rm -r "{}"

Executing it via SSH shows that it completes without issue but when it runs from a Cron Job i get:

Quote:
/bin/sh: -c: line 0: unexpected EOF while looking for matching `''
/bin/sh: -c: line 1: syntax error: unexpected end of file

Any help is much appreciated. Thanks
# 2  
Old 02-04-2013
Code:
-printf '"\%p"\n'

This User Gave Thanks to vgersh99 For This Post:
tiagom
# 3  
Old 02-04-2013
Changing it to
Code:
-printf '"\%p"\n'

and using
Code:
find -P /home/user/mail/domain/ -mindepth 2 -mtime '+366' -type f -printf '"\%p"\n' | grep -v '/Important' | grep -v '/.Important' > /home/electro/mail/Logs/emails.list

to output the results to a file i receive
Quote:
find: warning: unrecognized escape `\%'
running from shell. Also the output file shows
Quote:
"\%p"
"\%p"
"\%p"
# 4  
Old 02-04-2013
% has a special meaning to cron. You must escape it when you put it directly in your crontab -- but only your crontab, not elsewhere.
This User Gave Thanks to Corona688 For This Post:
tiagom
# 5  
Old 02-04-2013
Great. Seems to be functioning.


Thank you very much
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