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awk - change date format

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# 8  
Old 01-25-2013
PLEASE use code tags as demanded!
I expect your specification to change again, for the 4th time, e.g. to accomodate for fields in double quotes as normally used in .csv files. And, how and why did field 6 change from ...12/3 to 1:23?
Why don't you give it a try yourself, having seen so many examples in the replies to your posts? Anyhow, use this as a starting point:
Code:
$ awk -F, '{split($3, Dt, "[/ :]"); printf "%4d%02d%02d,%02d%02d00,%s,%s,%s,%s,%s\n", Dt[3],Dt[2],Dt[1],Dt[4],Dt[5],$1,$2,$4,$5,$6}' file
20120809,030000,123456789,98765432,1, ABC ABC, NEW STRING (12/3)

This User Gave Thanks to RudiC For This Post:
vegasluxor
# 9  
Old 01-25-2013
Below solution worked! Thanks all for ur help.

Code:
awk -F , '{
          
        split($3,a," ")
        var1=a[1]
        var2=a[2]
        split(var1,a,"/")s    ### Separate date
        printf("%02s%02s%02s,",a[3],a[2],a[1])
        split(var2,b,":")      ### Separate time
        printf("%02s%02s00, ,",b[1],b[2])
        ### End of date and time

        printf("%s,%s,%s, , ,0,%s, , , ,I, , , ,\n",$1,$2,$4,$7)
            
         }' a.csv

Last edited by Scrutinizer; 01-25-2013 at 06:38 AM.. Reason: code tags
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