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Shell Programming and Scripting

Supressing lines starting with #

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# 1  
Old 01-21-2013
Question Supressing lines starting with #
Ok, I should know how to do this...
I want to run crontab -l and pipe it through sed so that only those lines that do not have a # as the first character show on the screen... I know Ive doen this before but its been a decade since I scripted anything

Im working in AIX 7.1 using the crontab command.

Anyway thanks for any help.
# 2  
Old 01-21-2013
Code:
crontab -l | sed '/^#/d'

This User Gave Thanks to vgersh99 For This Post:
immagikman
# 3  
Old 01-21-2013
DoH! Thank you I was leaving out the carrat :P Dumb dumb dumb.....thanks again.
# 4  
Old 01-21-2013
Using grep:

Code:
crontab -l | grep -v '^#'

This User Gave Thanks to mjf For This Post:
immagikman
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