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Capture listed files from find command

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# 1  
Old 01-17-2013
Capture listed files from find command
Hi all,

I am using command
Code:
find $InputPath -type f -mtime +30

However, I need to capture the file listed in screen.
May I know how to achieve this?


Thank you.
# 2  
Old 01-17-2013
Use redirection (man shell) and/or tee cmd.
# 3  
Old 01-17-2013
Hi,

Is this the correct syntax?

Code:
echo [`date +"%Y-%m-%d %T"`] "---------------" | tee -a $LogPath/$LogFile
find $InputPath -type f -mtime +30 | tee -a $LogPath/$LogFile
echo [`date +"%Y-%m-%d %T"`] "---------------" | tee -a $LogPath/$LogFile

But I need the date in front of the files.


Please advise.
Last edited by ashly; 01-17-2013 at 05:06 AM..
# 4  
Old 01-17-2013
This is not what you requested in your first post. Pls show us our desired output.
# 5  
Old 01-17-2013
Hi,

Current output as below:
PHP Code:
[2013-01-17 16:53:02]---------------
filename1
filename2
[2013-01-17 16:53:02]--------------- 
Desirable output:
PHP Code:
[2013-01-17 16:53:02]---------------
[2013-01-17 16:53:02]filename1
[2013-01-17 16:53:02]filename2
[2013-01-17 16:53:02]--------------- 
# 6  
Old 01-17-2013
Quote:
Originally Posted by ashly
Hi,

Is this the correct syntax?

Code:
echo [`date +"%Y-%m-%d %T"`] "---------------" | tee -a $LogPath/$LogFile
find $InputPath -type f -mtime +30 | sed "s/^/'[`date +"%Y-%m-%d %T"`]/" | tee -a $LogPath/$LogFile
echo [`date +"%Y-%m-%d %T"`] "---------------" | tee -a $LogPath/$LogFile

But I need the date in front of the files.


Please advise.
Try the above highlighted!!!

Cheers,
RangaSmilie
# 7  
Old 01-17-2013
Quote:
Originally Posted by rangarasan
Try the above highlighted!!!

Cheers,
RangaSmilie
Hi Ranga,

I tried but I got the error below:
PHP Code:
sed: 0602-404 Function s/^/'[2013-01-17 cannot be parsed. 
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