Shell Programming and Scripting

I am interested in 2 and 36th fields in this input file. I was wondering if there was a more efficeint way to do this.

($pt1,$bkup_name,$pt3,$pt4,$pt5,$pt6,$pt7,$pt8,$pt9,
$pt10,$pt11,$pt12,$pt13,$pt14,$pt15,$pt16,$pt17,
$pt18,$pt19,$pt20,$pt21,$pt22,$pt23,$pt24,$pt25,
$pt26,$pt27,$pt28,$pt29,$pt30,$pt31,$pt32,$pt33,
$pt34,$pt35,$tcpname,$pt37)=split(/,/,$tmpArr[$x]);

Code:

awk -F"," { print $2,$36 }' filename

Same efficiency, just a twist in the way you get the params:

Code:

@fieldAry = split(/,/,$tmpArr[$x]);
@wantedFieldAry = @fieldAry[1..35];

Sorry. Thought you wanted another way, outside perl.

Thanks guys.
Jim I was looking for a perl solution.

Just thought I'd revisit this cause I discovered that you can get to a specific field by using a splice. If I want the 2nd and 36th field you can do

($field2,$field36) = (split /,/, $tmpArr[$x]) [2,36];

Hope this is helpful to others.

Hmm. Then you are extracting the 3rd and the 37-th in this case. Are you (assuming you have a default value of $[ )?

By the way, I think I made an error in my earlier post. I meant to use [1,35] instead of [1..35]. Didn't see until you bring up this today.