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Sudo function

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# 1  
Old 01-13-2013
Sudo function
I have my .bash_profile with this function for instance:
Code:
foo(){
   if [ `id -u` -ne 0 ]
      then   echo "RUN COMMAND AS ROOT"
      else   echo "F-O-O"
   fi
}

If I launch terminal (MAC OSX) and run foo it'll output RUN COMMAND AS ROOT as expected.

BUT.

If I run sudo foo output is sudo: foo: command not found.

I can always:
Code:
$ sudo -s
[password]
$ source ~/.bash_profile
$ foo

That will work, but I'd rather have a fast way of doing it.
Any tips?
# 2  
Old 01-13-2013
sudo is not psychic, hence it does not know what aliases and functions you have in your shell.

sudo can only run things that are files. It cannot run aliases and functions.

Why can't this "foo" run sudo itself?
# 3  
Old 01-13-2013
Quote:
Originally Posted by Corona688
sudo is not psychic, hence it does not know what aliases and functions you have in your shell.

sudo can only run things that are files. It cannot run aliases and functions.

Why can't this "foo" run sudo itself?
I must assume then there's no possible way of doing this?

Thanks.
# 4  
Old 01-13-2013
Quote:
Originally Posted by dasx
I must assume then there's no possible way of doing this?
sudo cannot run shell functions and aliases. These are shell-builtins, unavailable to anything else outside the shell.

You could put 'foo' into a script file, and have sudo run that.
# 5  
Old 01-13-2013
You could also source $HOME/.bash_profile and run foo using the -c arg to bash eg:

Code:
sudo /bin/bash -c "source $HOME/.bash_profile ; foo"

I'm unsure if the .bash_profile you refer to is root's or the user's if you want root's profile try::

Code:
sudo /bin/bash -c 'source ~/.bash_profile ; foo'

This User Gave Thanks to Chubler_XL For This Post:
dasx
# 6  
Old 01-14-2013
Quote:
Originally Posted by Chubler_XL
You could also source $HOME/.bash_profile and run foo using the -c arg to bash eg:

Code:
sudo /bin/bash -c "source $HOME/.bash_profile ; foo"

I'm unsure if the .bash_profile you refer to is root's or the user's if you want root's profile try::

Code:
sudo /bin/bash -c 'source ~/.bash_profile ; foo'

That does actually work! Thanks!
I was trying to set a function or an alias to do the most part of the writing for me (because if not, this still is faster: sudo -s; source .bash_profile; foo).

Tried this but didn't work:

Code:
suddo(){
	sudo /bin/bash -c 'source ~/.bash_profile ; $1'
}

Doesn't give any error nor it dosn't work.
Do you come up with something?


Thanks!!
# 7  
Old 01-14-2013
The shell won't expand variables (like $1) when enclosed in single quotes.
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