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All strings within two special chars

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# 1  
Old 01-12-2013
All strings within two special chars
I have a file with multiple lines. From each line I want to get all strings that starts with '+' and ends with '/'. Then I want the strings to be separated by ' + '

Example input:
Code:
+$A$/NOUN+At/NSUFF_FEM_PL+K/CASE_INDEF_ACC

Sample output:
Code:
$A$ + At + K

# 2  
Old 01-12-2013
Try:
Code:
perl -nle 'print join " + ", map {s/[\+\/]//g;$_} /\+.*?\//g' file

This User Gave Thanks to bartus11 For This Post:
Viernes
# 3  
Old 01-12-2013
May need some polishing:
Code:
$ sed 's:$:+:;s:^+::;s:/[^+]*+: + :g;s: + $::' file
$A$ + At + K

# 4  
Old 01-12-2013
Thanks! That works. Except that for some lines, there isn't a + at the start.
So is there a way to insert a '+' on each line only when there isn't one?
Then your suggested code will work.
# 5  
Old 01-12-2013
Quote:
Originally Posted by Viernes
Thanks! That works. Except that for some lines, there isn't a + at the start.
So is there a way to insert a '+' on each line only when there isn't one?
Then your suggested code will work.
Your specification of what should happen when there are no + and/or / characters and when + and / characters don't appear as pairs resulted in different people trying to help making different assumptions. If you answer the following questions, we can probably provide something that will do what you want:
  1. If there is text before the 1st + with a terminating / on a line, should that text be skipped?
  2. If there is no + with a terminating /, should the line be:
    1. ignored completely,
    2. be replaced by an empty line, or
    3. be copied to the output without change.
  3. If there is a + between a + and a /, should:
    1. the 1st + start the field and any more +s before the / be printed as is, or
    2. should leading + signs be discarded as text that is not between a + and a /?
  4. If there is a + on a line with no / following it (after a + with a matching / has been found), should:
    1. the + and any text following it be discarded,
    2. the + be disarded but any following text be copied to the output, or
    3. should the remainder of the line be copied to the output as thought a trailing / appeared at the end of the line?
If the answer to question 1 is yes, 2 is C, 3 is A, and 4 is A, the following awk script should do what you want:
Code:
awk '{  while(match($0, "[+]([^/])*[/]") > 0) {
                o = (o != "" ? o " + " : "") substr($0, RSTART + 1, RLENGTH - 2)
                $0 = substr($0, RSTART + RLENGTH)
        }
        if(o != "") print o
        else print
        o=""    
}' input

As always with awk, if you are using a Solaris system, use /usr/xpg4/bin/awk or nawk, instead of awk.
When the file input contains:
Code:
+$A$/NOUN+At/NSUFF_FEM_PL+K/CASE_INDEF_ACC
before+$A$/NOUN+At/NSUFF_FEM_PL+K/CASE_INDEF_ACC
before+$A+B$/NOUN+At/NSUFF_FEM_PL+K/CASE_INDEF_ACC
this line has no terminating slash+data after plus
this line has no starting plus sign/after slash
+this whole line is a single field between a plus sign and a slash/
+++++++++++++++++++++++++++
+previous line was a string of plus signs/
///////////////////////////
+previous line was a string of slashes/
++++++++++//////////
+previous line was 10 plus signs followed by 10 slashes/
+D=A+B+C/

this script produces:
Code:
$A$ + At + K
$A$ + At + K
$A+B$ + At + K
this line has no terminating slash+data after plus
this line has no starting plus sign/after slash
this whole line is a single field between a plus sign and a slash
+++++++++++++++++++++++++++
previous line was a string of plus signs
///////////////////////////
previous line was a string of slashes
+++++++++
previous line was 10 plus signs followed by 10 slashes
D=A+B+C

# 6  
Old 01-13-2013
Yes you have a point. I apologise about this.

1. No, it shouldn't be skipped. So for
Code:
Al/DET+>ax/NOUN+

I want to get
Code:
Al + >ax

2. A. If there is no '+' nor '/', the line should be skipped. Although the file doesn't contain such a line.
3. Use the '+' as the delimiter in this case.
So for
Code:
Al+>ax/NOUN+
Al+>a+x/NOUN+

I want to get
Code:
Al + >ax
Al + >a + x

4. A
# 7  
Old 01-13-2013
Insert a plus at the start when there isn't one and the line contains at least one character:
Code:
sed 's/^[^+]/+&/' file

Last edited by Scrutinizer; 01-13-2013 at 02:00 AM..
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