Shell Programming and Scripting

In a CSH, i need to write a loop to seach continuously for text "Started" and then only exit from the loop when ever if finds that.

Can someone please suggest how we can write this
Thanks,
Sateesh

People are going to tell you not to use csh, but that's up to you.

What have you done so far? Please post some sample code so we can see where you're having problems. Also, where is the text "Started" - in a growing log file that's being appended to, in random files scattered over the filesystem, etc, etc????

Cheers
ZB

Hi,

My script is below and i am getting error "if:Expression Syntax" when i run this.
Could someone please help why i am getting this error?

-----
#!/bin/csh
set count = 0
set timecount = 0
while ($count < 1)
set count=`grep "Engine finished startup" /home/ficctprd/KA_SWCCT_PROD_NY_nbswpsa52/log/keepalive.lo
g |wc -l`
echo "Sleeping for 60 Seconds"
#sleep 60
set timecount = `expr $timecount + 1`
if ( $timecount -gt 4 )
then
echo "Not Started Successfully"
break
endif
end
echo $count
echo $timecount
------

Try this

Code:

#! /bin/csh

set count = 0
set timecount = 0

while ($count < 1)
set count=`grep -c "Engine finished startup" /home/ficctprd/KA_SWCCT_PROD_NY_nbswpsa52/log/keepalive.log`
echo "Sleeping for 60 Seconds"
#sleep 60
set timecount = `expr $timecount + 1`
if ($timecount > 4) then
echo "Not Started Successfully"
break
endif
end
echo $count
echo $timecount

I have changed your grep statement as well. The -c will give you the count.

vino