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Grep problem

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# 1  
Old 01-04-2013
Grep problem
i have a log file...in that there is a data like
Code:
oss1 F:\app\data\misc\server  012-07-31 08:35:15            8.1.1.
oss2 F:\app\data\misc\server  012-07-31 08:36:15            8.1.2.
oss3 F:\app\data\misc\server  012-07-31 08:37:15            8.1.3.
pss4 F:\app\data\misc\server  012-07-31 08:38:15            8.1.4.
oss5 F:\app\data\misc\server  012-07-31 08:39:15            8.1.5.
oss6 F:\app\data\misc\client  012-07-31 08:40:15            8.1.6.
pss5 F:\app\data\misc\client  012-07-31 08:4115            8.1.7.


i want the output which is having "F:\app\data\misc\server" only

i tried cat logfile.txt|grep "F:\app\data\misc\server"
not working
may i know the reason why its not working????and als need the grep command to filter the results

Moderator's Comments:
Mod Comment Please use code tags next time for your code and data.
Last edited by radoulov; 01-04-2013 at 04:56 PM..
# 2  
Old 01-04-2013
Try escaping the back slash \
Code:
grep 'F:\\app\\data\\misc\\server' logfile.txt

From grep manual:

Care should be taken when using the characters $, *, [, ^, |, (, ), and \ in expression, because they are also meaningful to the shell.

It is safest to enclose the entire expression argument in single quotes ('...').
This User Gave Thanks to Yoda For This Post:
navsan420
# 3  
Old 01-04-2013
Maybe either single quotes OR escape but not both?
# 4  
Old 01-04-2013
DGPickett, I think it should be single quotes AND escape both.
# 5  
Old 01-04-2013
Single quotes pass \ intact, but double quotes see \ as an escape to put a double quote into the string:
Code:
$ echo '\'|cat -vte
\$
$ echo "\"|cat -vte
> ^C
$

I use single quotes first and most for their almost complete immunity to unintended meta-behavior. I figure it saves cycles in the shell.

But, hey, the answer is in there somewhere. I flash on FRED buffer scripts where we were seeing 4 or even 8 \ as the number halved every time you went through a meta-wall like the buffer! Smilie
# 6  
Old 01-04-2013
also in this case its not working
Code:
while read LINE
	 do
   echo  $LINE | grep 'F:\\app\\data\\misc\\server'  | grep -v Running 
    done <logfile.txt

But it takes as
Code:
while read LINE
	 do
   echo  $LINE | grep 'appdatamiscserver'  | grep -v Running 
    done <logfile.txt

is there any possible way to get as it is??
# 7  
Old 01-05-2013
Look what the shell does to your command (using bash's -vx option):
Code:
$ grep 'F:\\app\\data\\misc\\server' file
+ grep 'F:\\app\\data\\misc\\server' file
$ grep "F:\\app\\data\\misc\\server" file
+ grep 'F:\app\data\misc\server' file
$ grep 'F:\app\data\misc\server' file
+ grep 'F:\app\data\misc\server' file

So - follow DGPickett's advice: "Maybe either single quotes OR escape but not both"
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