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Grep problem

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# 8  
Old 01-05-2013
Another issue,
In the output file there are 10 lines having the status Running ..i am getting the output as 10 for the below command...
Code:
cat output.log |grep 'F:\\app\\data\\misc\\server'| grep Running| wc -l

But when i execute as ksh file it gives wrong output..i am getting RED..
means 0 lines having the status Running(if i give (SERVER_STATUS -eq 0) its showing GREEN)
Code:
SERVER_STATUS=`cat output.log |grep 'F:\\app\\data\\misc\\server'| grep Running| wc -l`

if [ $SERVER_STATUS -eq 10 ]
then
     echo "GREEN"
else
     echo "RED"
fi

Last edited by navsan420; 01-05-2013 at 03:54 PM..
# 9  
Old 01-05-2013
Replace back-ticks ` ` with $( ). Also no need to use cat and wc
Code:
SERVER_STATUS=$( grep 'F:\\app\\data\\misc\\server' output.log | grep -c Running )

# 10  
Old 01-05-2013
Getting Error..
Code:
test.ksh[2]: 0:  not found
test.ksh[4]: test: argument expected
RED

# 11  
Old 01-05-2013
It is difficult to tell what is the issue without seeing the code. Can you set xtrace, run and post the results:
Code:
#!/bin/ksh -x

# 12  
Old 01-05-2013
Code:
test.ksh[2]: 10:  not found
test.ksh[4]: test: argument expected
RED

# 13  
Old 01-06-2013
you can use sed command right
# 14  
Old 01-06-2013
Try either
Code:
SERVER_STATUS=$( grep 'F:\app\data\misc\server' output.log | grep -c Running )

or
Code:
SERVER_STATUS=$( grep "F:\\app\\data\\misc\\server" output.log | grep -c Running )
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