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awk and cut command

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# 1  
Old 01-04-2013
awk and cut command
Hi,
I have to display the value 16 present in "lcpu=16" which is the output of a command
Code:
# vmstat
System configuration: lcpu=16 mem=4096MB

I used as

Code:
#  hdtype=`vmstat |  grep "lcpu" | awk -F "=" '{print $2}'`
# echo $hdtype
16 mem

But I need to display only 16..
Am doing some error in awk..
Please help..
Thanks in advance..
# 2  
Old 01-04-2013
Code:
hdtype=$(vmstat | awk -F"[ =]" '/lcpu/ {print $4}')

# 3  
Old 01-04-2013
Code:
 
hdtype=`vmstat |  awk -F= '/lcpu/{print $2+0}'`

if you in solaris, then use nawk
# 4  
Old 01-04-2013
Smart way of removing the text Smilie this works ok if text is at the start of the field.
But I do suggest use $() instead of ``, more easy to read.
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