Print unique names in each row of a specific column using awk

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# 1  
Old 12-12-2012
Print unique names in each row of a specific column using awk

Is it possible to remove redundant names in the 4th column?


cqWE    100    200    singapore;singapore
AZO    300    400    brazil;america;germany;ireland;germany

cqWE    100    200    singapore
AZO    300    400    brazil;america;germany;ireland

# 2  
Old 12-12-2012
With Perl you could write something like this:

perl -lpe'
  %_ = ();
  s/[^\s]+$/join ";", grep !$_{$_}++, split ";", $&/e
  ' infile

With awk the code will be more noisy.

Last edited by radoulov; 12-12-2012 at 01:20 PM..
# 3  
Old 12-12-2012
a 'noisy' awk: awk -f quincy.awk myFile
  n=split($4, a,";")
    if( !(a[i] in t)) {
      $4=(i==1)?a[i]:$4 ";" a[i]

This User Gave Thanks to vgersh99 For This Post:
# 4  
Old 12-12-2012
Smilie Smilie
# 5  
Old 12-12-2012
If you want/prefer to use awk and you have a recent GNU awk implementation,
you could reconstruct the records after the change exactly (including variable FS')
and preserve the original formatting:

awk '{
  split($0, t, FS, s)
  for (i = 0; ++i < NF;)
    printf "%s", $i s[i]
  n = split(t[i], tt, fs)
  delete _; lf = x
  for (i = 0; ++i <= n;)
    lf = lf (_[tt[i]]++ ? x : tt[i] fs) 
  print substr(lf, 1, length(lf) - 1)
  }' fs=\; infile

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