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Working with grep-output

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# 1  
Old 12-12-2012
Working with grep-output
Hi, 1st post

Sorry for borrowing the thread.

Hopefully this is doable.

I need to write a script where I need to pick information from my grep-results.

Code:
grep -n "s_" file | head -n 1

Output is like this:
Code:
6:s_9: 11-664 Fam_g442_99

So this gives me the first line of the file which includes "s_" .

I need to pick those s_9, 11-664 and Fam_c606_1 separately that the script can rename the txt-file's subfolders with this information.

After this is done, my script will do the grep with | head -n 2 and repeat the sequence.

Many thanks in advance
Last edited by Scrutinizer; 12-12-2012 at 08:50 AM.. Reason: code tags
# 2  
Old 12-12-2012
Code:
#!/bin/bash
declare -a array=( $(awk  -F '[ :]'   '$2 ~ /^s_/  {printf("%s %s %s ", $2, $3, $4) }' filename ) )
# you now have an array of name pieces
# you can access them as groups of three:

element=0
while [ $element -lt ${#arr} ]
do
     part1=${arr[element]}   
     element=$(( $element + 1 ))
     part2=${arr[element]}
     element=$(( $element + 1 ))   
     part3=${arr[element]}   
     element=$(( $element + 1 ))
     echo "part1=$part1  part2=$part2 part3=$part3"
     # rename your files here
done

# 3  
Old 12-13-2012
Thanks in advance!

I'll give it a try
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