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How to count number of files in directory and write to new file with number of files and their name?

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Top Forums Shell Programming and Scripting How to count number of files in directory and write to new file with number of files and their name?
# 8  
Old 12-09-2012
You will have to redirect into a file.

Code:
echo "Number of files in the directory = `ls -ltr | grep -v '^d' | wc -l` >file
ls -ltr | grep -v '^d' | cut -c 59-100 | awk '{ print NR". "$0}' >>file

# 9  
Old 12-09-2012
result is wrong..my dear..
# 10  
Old 12-09-2012
If you are deploying awk anyhow, why don't you do it extensively:
Code:
ls -l|awk '/^-/{Ar[++n]=$9} END {print "No. of files: ", n; for (i=1;i<=n;i++) print i".", Ar[i]}'

This User Gave Thanks to RudiC For This Post:
PikK45
# 11  
Old 12-09-2012
Wrench
So, can we have the folder details??

---------- Post updated at 04:04 PM ---------- Previous update was at 03:59 PM ----------

Quote:
Originally Posted by RudiC
If you are deploying awk anyhow, why don't you do it extensively:
Code:
ls -l|awk '/^-/{Ar[++n]=$9} END {print "No. of files: ", n; for (i=1;i<=n;i++) print i".", Ar[i]}'

Thanks RudiC Smilie

So I agree that the above code will work. What if the file name contains <space>?

UNIX systems doesn't allow that naming, but windows does. Even the O/P provided at the beginning has such a name.Smilie
# 12  
Old 12-09-2012
Quote:
Originally Posted by PikK45
So I agree that the above code will work. What if the file name contains <space>?
You are right - what I posted was thought to be an example/hint on how to improve, not a full blown solution. You'd need to concatenate ALL trailing fields into Ar to account for that, like AR[++n]=$9" "$10... or Ar[++n]=substr($0,50). Neither of these is really satisfying. I'd prefer to use sth. likestat on systems where it is available.
Code:
stat -c"%F   %n" *| awk  -F"\t" '/^regular/{Ar[++n]=$2} END {print "No. of files: ", n; for (i=1;i<=n;i++) print i".", Ar[i]}'

Last edited by RudiC; 12-09-2012 at 07:11 AM..
# 13  
Old 12-09-2012
This is output of stat command
Code:
admin@las:~/Desktop/file_make/datafilter$ stat -c"%F   %n" *| awk  -F"\t" '/^regular/{Ar[++n]=$2} END {print "No. of files: ", n; for (i=1;i<=n;i++) print i".", Ar[i]}'

No. of files:  7
1. 
2. 
3. 
4. 
5. 
6. 
7.

---------- Post updated at 06:29 AM ---------- Previous update was at 06:28 AM ----------

This is using awk

Code:
admin@las:~/Desktop/file_make/datafilter$ ls -l|awk '/^-/{Ar[++n]=$9} END {print "No. of files: ", n; for (i=1;i<=n;i++) print i".", Ar[i]}'

No. of files:  7
1. a.txt
2. data_filter.sh
3. data_filter.sh~
4. data_filter.txt
5. data_filter.txt~
6. dir.sh
7. dir.sh~

# 14  
Old 12-09-2012
Code:
stat -c"%F   %n" *|
           ^--- You need a <TAB> char here!
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