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Get the list with sed or awk

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# 1  
Old 12-04-2012
Get the list with sed or awk
Code:
#cat file
[General]
aa
bb
cc
[Sabino B]
dd
ee
[XXX C]
[QQQ D]
[zzz D]
77
dd
[FAFS EE]
gg
xx

I want to get: when VAR="zzz D" get below out put
Code:
aa
bb
cc
77
dd

the rules is add General items to zzz D item. and get the list
# 2  
Old 12-05-2012
Try

Code:
awk '/^\[/{a=""}
a{print}
/\[General\]/{a=1}
/\[zzz D\]/{a=1}' file

# 3  
Old 12-05-2012
Quote:
Originally Posted by pamu
Try

Code:
awk '/^\[/{a=""}
a{print}
/\[General\]/{a=1}
/\[zzz D\]/{a=1}' file

Thanks, it works,can you explain it to me

Lei
# 4  
Old 12-05-2012
Quote:
Originally Posted by yanglei_fage
Thanks, it works,can you explain it to me

Lei
Minimized by one more line...Smilie
Code:
awk '/^\[/{a=""}                          # If line starts with "[" (means VAR) set a="" (null)
a{print}                                  # If a is present then print
/\[General\]|\[zzz D\]/{a=1}' file      # If line contains [General] or [zzz D]  then set a=1, So that we can print all the lines after these values.

I hope this helpsSmilie

pamu
# 5  
Old 12-05-2012
Quote:
Originally Posted by pamu
Minimized by one more line...Smilie
Code:
awk '/^\[/{a=""}                          # If line starts with "[" (means VAR) set a="" (null)
a{print}                                  # If a is present then print
/\[General\]|\[zzz D\]/{a=1}' file      # If line contains [General] or [zzz D]  then set a=1, So that we can print all the lines after these values.

I hope this helpsSmilie

pamu
I understand it partly, if change zzz D to a variable, can we get it eg: VAR="zzz D"
# 6  
Old 12-05-2012
Through Sed..
Code:
$ uname -rs
SunOS 5.10
$ sed -n 'H;${
x
s/[^]]*]\n\([^[]*\).*\[zzz D\]\n\([^[]*\)\n.*/\1\2/p
}' inputfile
aa
bb
cc
77
dd
$

# 7  
Old 12-05-2012
Code:
awk '/^\[/{a=""}
a{print}
$0~"[General]" || $0~var {a=1}' var="[zzz D]" file

Edit: This gives to much, not sure whats wrong
Last edited by Jotne; 12-05-2012 at 02:17 AM..
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