Shell Programming and Scripting

What system are you using? If it is a Solaris system, try using /usr/xpg4/bin/awk or nawk instead of /usr/bin/awk.

If it is a Solaris system, there is also a good chance that nextfile isn't supported, but that should have generated a clearer error message. Have you tried the other form:

Code:

find . -name 'a.txt' -exec awk -F'|' 'FNR==1{printf("%s %d\n", FILENAME, NF-1)}' {} +

Hi Guys, thanks again for swift responses on this. I managed to solve my problem - so thought I would share - feel free to comment. Also have another question. So just for everyone's benefit in the code below I am

1. Doing recursive find of the .txt files
e.g. /folder1/folder2/folder3/a.txt
2. Pulling out the first row of each of the .txt files
e.g. from a.txt take only first row abc|def|efg
3. Count number of | strings into temp2 variable
4. Count number of / strings from the path name into temp3
5. I only want to output paths which have a set number of / strings (only 9 and 10)

SO HERE'S THE NEW QUESTION:
so for the check on the number of / string I have the OR clause but what actually happens is that it finds paths which have 10 strings it it and outputs them but does not look at any with 9 in them. equally if I swap the code around it find the paths with 9 in them but does not look at any with 10. Is there a better way to do this other than split up the if statement?

Code:

find . -name .snapshot -prune -o -name "*.txt" -print|while read i
do
    temp1=`grep "|" "${i}"|head -1`
    temp2=`echo ${temp1} | awk -F"|" '{c += NF - 1} END {print c}'`
    temp3=`echo ${i} | awk -F"/" '{c += NF - 1} END {print c}'`
    echo $temp3
    if [ "$temp3" = "10" -o "&temp3" = "9" ]; then
      echo "${i} , ${temp3} , ${temp2}"
      echo
    fi
done

Does your find provide the -mindepth and -maxdepth options? That would help in the first place. If it does not, why don't you filter find's output before reading it into the i variable?