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Python Binary File Read and Parse

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Old 11-30-2012
Question [SOLVED] Python Binary File Read and Parse

Hi to everyone Smilie, i have a challenge right now in python that for now needs a bit of help in one part of the c0de.
The task is create a new file with the name of the file defined by the ASCII content between the 3 byte and the 16 byte that is parsed from the binary file, the file is over 20 Mb i need to create a file for each record ( each record contains the len of 820 ), so right now i know how to read it and do something with it, like :


with open("file", "rb") as f:
	byte =
	if byte > 820:
	    print "Reach the 1 record mark on the File you have defined "

Now the problem is , how do i get the name file that i want that is the string between the 2 byte and the 16 byte and how to save every 820 bytes to a new file like :

#attention noob code coming for quick understading i have a for loop for #example not for use i have to use it for the each 820 bytes new file
#with the read of the 820 bytes on the new file and save it and go for the
#next 820 bytes and so on until the end of the file.
for in file:
    if = 820:
       a =
       b = open("Iam_from_2_to_16_byte_string", w)

---------- Post updated 30-11-12 at 10:26 AM ---------- Previous update was 29-11-12 at 10:42 AM ----------

here is the solution :
n = 820
with open('/home/drdos/work/file.PDA', "rb") as f:
    while True:
        data =
        if not data:
        filename = str(data[16:32])
        x = open(filename, 'wb').write(data)

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