Shell Programming and Scripting

Hi,

I have some problem in assigning values to variables: This is what Iam literally doing:

i=0
input=test
temp$i = $input

In the sense, I try to assign the value in the variable input (ie., test) to another variable temp0 (since i is assigned 0, temp$i is temp0). Seems simple, but I get this error...

ksh: temp0: not found.

The first 2 lines are correct - I checked using echo$i and echo $input commands... but echo $temp0 is null!!

Any idea on where I miss...

any help is highly appreciated...

Thanks,
Mohan

using arrays you can do this:

#initialise i
i=0

#initialise input
input=test

#assign $input to specified array element
temp[$i]=$input

#echo array value at pos i
echo ${temp[i]}

You must use eval statement :

i=0
input=test
eval temp$i = $input

But the best solution is using array (see rein post)


Jean-Pierre.

Thanks rein.. (apologies for late reply)..

This method is now working fine.. Never realized the concepts of arrays..

Thanks aigles ..