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Passing user argument

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# 1  
Old 11-21-2012
Passing user argument
Hi all:

I'm trying to pass an argument to a command but it's being difficult.

Code:
#!/bin/bash
set -xv

if [ "$#" -gt 1 ]; then
  echo "More than 1 argument entered"
  echo "Please enter a month using 3 character names, ie, Jan, Mar, Apr, Dec" && exit 1
fi

if [ "$#" -eq 0 ]; then
  echo "Please enter a month using 3 character names, ie, Jan, Feb, Jun, Oct, Nov" && exit 1
fi

echo "$1"

cat ti.files | perl -ne '/.tgz$/ && !/blockpool/ && !/core.tgz/ && print' | awk '{if (($6 == ?????) && ($5 < 20000000) && ($5 > 1000000)) print $0}' | sort -nk7

Each line if the 'ti.files' is a line from the output of 'ls -la'. So the $6 position is the month, $5 is the file size, etc.

What is suppose to happen, the script is executed from command line and the user supplies a month name.
Quote:
Example, 'runme Oct'.
That month is to be in the position where the ????? marks are.

But that is not happening. Little help, please?

Many thanks!
# 2  
Old 11-21-2012
Code:
 
awk '{if 
 
to
 
awk -v mon="$1" '{if (($6 == mon)

---------- Post updated at 12:54 PM ---------- Previous update was at 12:51 PM ----------

you can try this

Code:
 
awk -v mon="$1" '/.tgz$/ && !/blockpool/ && !/core.tgz/{if($6==mon && $5 < 20000000 && $5 > 1000000)print}' ti.files | sort -nk7

This User Gave Thanks to itkamaraj For This Post:
raggmopp
# 3  
Old 11-21-2012
Or (not tested):
Code:
perl -lane 'BEGIN{$mon=shift @ARGV}
print if (/\.tgz\z/          and
          !/blockpool/       and
	  !/core\.tgz/       and
	  $F[5] eq $mon      and
	  $F[4] < 20_000_000 and
	  $F[4] > 1_000_000)' "$1" ti.files|sort -nk7

Last edited by elixir_sinari; 11-21-2012 at 10:54 PM..
This User Gave Thanks to elixir_sinari For This Post:
raggmopp
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