Shell Programming and Scripting

Hi Friends,

I have developed a standalone java application which is deployed in a Linux environment. I have created a script for starting this application if the process is not running or else do nothing.
The application is deployed as a .jar. I have also created a crontab entry like this...

Code:

*/1 * * * * /app/prd-data/abc/def/xyzMonitor.sh

This is the contents of the xyzMonitor.sh script...

Code:

#!/bin/bash 
# check daemon 
ps -ef | grep -v grep | grep common.App 
# if not found - notequals to 0, start it 
if [ $? -ne 0 ] 
then 
nohup /app/wl-data/Oracle/Middleware/jdk160_21/bin/java -cp Application.jar *.common.App & 
else 
echo "XYZ Watcher already running - do nothing" 
fi

The issue now is that even after one minute the crontab is not picking the script for running this application.
Can someone help me what is the issue here, whether the script is not correct or any others.

P.S: I am a Linux noob and this development is done for my company. I have done the deployment by getting info from various websites. So I might be wrong in this.
Experts please advice to solve this issue.



Thanks in advance,
Binoy

You can just use:

Code:

 * * * * * /app/prd-data/abc/def/xyzMonitor.sh

And check crontab log, if it`s runs correctly.