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Shell Programming and Scripting

Percentage Calculation in Decimal

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# 15  
Old 11-30-2012
Quote:
Originally Posted by Anupam_Halder
one more problem ..

what if the value is 12.55? It will make it 12.56 right?
And also we may need to take care many more things Smilie

Like it's not only that I will get 12.55

I may get 1.155 --> And it should give me 1.16
Yes it will make any number having .55 to .56

for your second and first condition use..Smilie

Code:
printf "%.2f\n" $(echo -e "scale=10\n(($b-$a)*100)/$b"|bc | awk -F "." '$2 ~ /^55|[0-9]55/{sub("55","56",$2)}1' OFS=".")

EDIT -

what if we use only awk..

Code:
echo "" | awk -v BB="$b" -v AA="$a" '{ s=(( BB - AA)* 100)/BB;
if(s ~ /\.55|\.[0-9]55/){split(s,P,".");sub("55","56",P[2]);s=P[1]"."P[2]};printf "%.2f", s}'

pamu
Last edited by pamu; 11-30-2012 at 07:55 AM..
# 16  
Old 11-30-2012
It seems that bash is using Round half down instead of the more commonly used Round half up.
So if you do not like this rule, you need to make a test for the number, and then round it up as in example of pamu.
# 17  
Old 11-30-2012
What Bash does in terms of rounding depends on the underlying libc sprintf() function. In most cases, sprintf() does unbiased rounding - not round half down or round half up.

In unbiased rounding, ‘.5' rounds to even. For example:
Code:
$ printf "%.0f\n"  1.5
2
$ printf "%.0f\n"  2.5
2
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