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What's wrong with this awk?

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Top Forums Shell Programming and Scripting What's wrong with this awk?
# 1  
Old 11-13-2012
What's wrong with this awk?
I have a file
and if I'm doing following action on that file it's coming up correctly

Code:
awk -F"," '/DATA_TYPE/ { cnt += $3 } END { print " DATA_TYPE count=" cnt}'  inter
 DATA_TYPE count=19593131

now if I'm changing same AWK, so that now it can accept variable, then it's somehow not working.
So can anyone, point me out what's wrong if variable passed to that same awk.

Code:
type="DATA_TYPE"
echo $type
DATA_TYPE
 awk -F"," -v type="$type" '/type/ { cnt += $3 } END { print type" count=" cnt}' inter
o/p= DATA_TYPE count=

# 2  
Old 11-13-2012
try

Code:
awk -F"," -v type="$type" '{if($0 ~ type) { cnt += $3 }} END { print type" count=" cnt}' inter

variables in awk doesn't work with /variable/

pamu
Last edited by pamu; 11-13-2012 at 09:49 AM..
# 3  
Old 11-13-2012
I think you can even leave the if out:
Code:
awk -F"," -v type="$type" '$0 ~ type { cnt += $3 } END { print type" count=" cnt}'

The /.../ construct has to contain a literal regex, so /type/ will search for occurrence of "type", not the contents of variable type.
Last edited by RudiC; 11-13-2012 at 12:11 PM..
# 4  
Old 11-13-2012
If you don't need a regular expression to match a pattern, don't use one. If you are looking for a literal string (as you were doing with /DATA_TYPE/), then either test for equality with == or use the index function.

Using a regular expression when not necessary, particularly a dynamic one, affords more opportunity for unintended results.

Regards,
Alister
This User Gave Thanks to alister For This Post:
vgersh99
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