Shell Programming and Scripting

Hello folks!
I am new to Shell and awk scripting.

This is my shell script that receives a string as an input from the user from the stdin.

Code:

#!bin/sh
printf "Enter your query\n"

read query
cmd=`echo $query | cut -f 1 -d " "`
input_file=`echo $query | cut -f 2 -d " "`
printf $input_file

if [ $input_file = "" ]
then
    printf "No input file specified\n"
    exit
fi
if [ $cmd = "summary" ]
then
    awk -f summary.awk $input_file $query
fi

Lets say he enters

Code:

summary a.txt some_other_options

Now "cmd" variable will take the value "summary" and "input_file" will take "a.txt".
Isn't that right?

I want summary.awk to work on $input_file, based on what is present in $query.
Isn't my approach right?

But when I run the shell script,
I get "awk: cannot open summary (No such file or directory)
"
I never intended to pass "summary" as my input file.
But it is the 1st word of $query. Is it getting perceived as the input file?
Why so?

My understanding is as follows :
1. The 1st command line argument passed is treated as input file.
e.g. : awk 'code' file arg1 arg2 arg3
only file is treated as input file

2. If the input file is piped, it doesn't see any of the arguments as input files.
e.g. : cat file | awk 'code' arg1 arg2 arg3
arg1 is NOT treated as input file.

Am I right?
Can you please help me?

Can you post the input file.. Try with nawk..

---------- Post updated at 04:45 AM ---------- Previous update was at 04:43 AM ----------

Added the path_name in the script

It gives the error even if the input file is :

Code:

{print}

---------- Post updated at 03:25 PM ---------- Previous update was at 03:24 PM ----------

The same error with nawk

---------- Post updated at 03:27 PM ---------- Previous update was at 03:25 PM ----------

And, are those 2 points I mentioned, right?

try:

Code:

#!/bin/sh
printf "Enter your query\n"

read cmd input_file

if [ $input_file = "" ]
then
    printf "No input file specified\n"
    exit
fi
if [ $cmd = "summary" ]
then
    awk -f summary.awk $input_file
fi

But my query doesn't consist just of 2 words :cmd and input_file
Typically, it might look like this :

Code:

summary file /o output_file /t something

First argument will be loaded into "cmd", the rest into "input_file".

[Update]
I just tried it.
It essentially gives the same error, only now it is "/o" as input file that is finds non-existent.

Code:

 summary file /o output_file /t something

This was again used as input.