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Regex: Get the word before match

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# 1  
Old 11-08-2012
Regex: Get the word before match
Hi

Input:
Code:
MYTEXT.aa.bb
cc.MYTEXT.aa.bb
ee.dd.cc.MYTEXT.aa.bb
cc.NOTEXT.a.b

Output:
Code:
<empty>
cc
cc
<empty>

I would like to use a regex to extract the last word before MYTEXT without the dot

Any tools can be used just it can take a regex input

Thx in advance
# 2  
Old 11-08-2012
try:
Code:
awk -F"[.]" '{w=""; for (i=1; i<=NF; i++) if ($i ~ /MYTEXT/) i>1 ? w=$(i-1) : 0; print w;}' in.txt

Last edited by rdrtx1; 11-08-2012 at 04:25 PM..
# 3  
Old 11-08-2012
Code:
perl -lne '/(\w+?)\.MYTEXT/ ? print $1 : print ""' file

Last edited by balajesuri; 11-08-2012 at 04:40 PM..
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