Shell Programming and Scripting

Hi,
I writing a shell program to remove the data from output of the find which matches a list in a file

I am using the below find command to get the list of files

x=`find . -name test*.dat`

the output of the find command is as follows

test1.dat
test2.dat
test3.dat
test4.dat
test5.dat

i have a file list.txt with the below search pattern

test4
test1


i need to remove the test4.dat and test1.dat from the variable x based on the data which is present in the file .

Kindly suggest me how to achive the same.

thanks
pals

Hi,

Please use code tags for code and data samples.

The code tag look like in the editor.

You can try below code snippet.

Code:

while read i;do x=$(echo "$x"|sed "s/.*\/$i.dat$//"); done <list.txt

I am assuming, you using bash shell. Please make sure that you should mention what system/shell are you using.

Cheers,
Ranga

try

Code:

x=$(find . -name test*.dat | grep -vf file)

Code:

echo "$x" | fgrep -v -f a.txt
test2.dat
test3.dat
test5.dat

Many thanks rangarasan and pamu for your help.both the command works perfectly.