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Print ALL matching words in a string

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# 1  
Old 11-07-2012
Print ALL matching words in a string
Hi.

Code:
str=" {aaID=z_701; time=2012-10-08 00:00:00.000}; {aaID=S_300; time=2012-10-08 00:00:00.000}]}; ansokningsunderlag={anmaln......}
{aaID=x_500; time=2012-10-08 00:00:00.000}]}; ansokningsunderlag={anmaln......}"

I want to print:

Code:
z_701
S_300
x_500

if I use :
Code:
echo $str | sed -n 's/.*aaID=\(.*\)time.*/\1/p'

the output is just the last hit.
Code:
x_500

How do i do to get all matches?

/Fred

Moderator's Comments:
Mod Comment Please use code tags next time for your code and data.
# 2  
Old 11-07-2012
You can try something like this:

Code:
$ echo $str | grep -o aaID=[^\;]* | cut -d= -f2
z_701
S_300
x_500

This User Gave Thanks to Subbeh For This Post:
freddan25
# 3  
Old 11-07-2012
With sed (with some assumptions):
Code:
echo "$str"|sed -n '/[^{]*{aaID=\([^;]*\);/{;s//\1\
/;P;D;}'

producing
Code:
z_701
S_300
x_500

These 2 Users Gave Thanks to elixir_sinari For This Post:
freddan25 gary_w
# 4  
Old 11-07-2012
Elixir_sinari, would you mind explaining the regex? I almost understand it but could use an explanation as I see this is a useful technique for extracting data from a line of a file.

Thank you!
Gary
# 5  
Old 11-07-2012
Using awk:-
Code:
echo $str | awk -F= ' { for (i=1; i<NF; i++) { if($i ~ /\{aaID/) print substr($(i+1),1,index($(i+1),";")-1); } } '
z_701
S_300
x_500

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