How to sort this?


 
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# 8  
Old 11-03-2012
I don't know what you are trying to do here. I thought you want to sort X points first and then the Y points. Can you explain the way you want the input sorted? It will be good if you can post a sample input & output required in code tags.
# 9  
Old 11-03-2012
Quote:
Originally Posted by bipinajith
I don't know what you are trying to do here. I thought you want to sort X points first and then the Y points. Can you explain the way you want the input sorted? It will be good if you can post a sample input & output required in code tags.
i did it in the first message
tip78
# 10  
Old 11-03-2012
I suggest you look for euler as well as for polar coordinate. The notation i used may then take a sens.

The logic i saw in the order you gave is that if you visualize the points in the order you mentionned, they could be ordered along a "kind of" spiral turning in the opposite sens to the trigonometric standard sens (or concentric circles). So an idea would be to convert cartesian coordinates to polar coordinates and then sort according their values (length & angle).

That was what i was trying to say in my first post : sort by increasing length and decreasing angles (you just have to care about taking an appropriate interval to express the value of the angle so that it fit with the order you expect).

---------- Post updated at 10:17 PM ---------- Previous update was at 09:45 PM ----------

I've just realized the |A| can decreasing so maybe the rule 1 to retain should be the angle ... or a combination of those polar coordinate...
... it looks this has already been asked here
# 11  
Old 11-03-2012
this is generation of matrix of coordinates which are not integers even

well i've found some kind of solution..
this is matrix:
Code:
3 3 3 3 3 3 3
3 2 2 2 2 2 3
3 2 1 1 1 2 3
3 2 1 0 1 2 3
3 2 1 1 1 2 3
3 2 2 2 2 2 3
3 3 3 3 3 3 3

when base x:y is 0:0 i'm doing next:
n=(1 to 100)
for every x+1 and x-1 i do y(-1 to +1. thats with 0 while X without 0. so Y is just 2 border-lines)
for every y+1 and y-1 i do x(-1 to +1)
for exery x+n and x-n i do y(-n to +n)
that's it
corners will have dublicates so n should be (n-1) and corners will be just constants for this 'n'

Last edited by tip78; 11-03-2012 at 07:28 PM..
tip78
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