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# 8  
Old 11-01-2012
Quote:
Originally Posted by ripat
... or a blend of the two solutions:
@Scrutinizer your snippet doesn't seem to return the expected result. At least on my sample file. Or is it me?
And same for your script also - don't give expected result.

I already tried with "\t" and space as delimiter..Smilie

please look..

Code:
awk '{print NF}' FS="[- ]" file
9
9
11
10
11
9

and

Code:
$ awk '{print NF}' FS="[-\t]" file
2
2
2
2
2
2

# 9  
Old 11-01-2012
Try with
Code:
FS="-| +"

Not sure how the fields are separated in the OP's sample file.
# 10  
Old 11-01-2012
Quote:
Originally Posted by ripat
... or a blend of the two solutions:
@Scrutinizer your snippet doesn't seem to return the expected result. At least on my sample file. Or is it me?
Quote:
Originally Posted by pamu
And same for your script also - don't give expected result.

I already tried with "\t" and space as delimiter..Smilie
[..]
The OP stated that the field separator is '\t' , so in order to use the input sample you first need to modify it by replacing any repetition of spaces by a single TAB character...
# 11  
Old 11-01-2012
Oh my bad. I missed that line. ok, even with \t as FS, I can not yield the same result with my snippet and yours. On the attached file

Code:
$ awk -F'[\t-]' 'p!=$1{if(p)print p, a/n, b/n; a=b=n=0; p=$1}{a+=$6; b+=$8; n++} END{print p, a/n, b/n}' file
05/18/12 19.9499 17.0846
05/19/12 15.3993 13.9434
05/02/12 15.9193 14.4067
05/13/12 13.2694 13.171
05/15/12 15.6814 13.6885
05/16/12 19.4222 17.1549
05/18/12 20.1258 17.0612
05/19/12 15.6013 13.9685


Code:
$ awk '{d5[$1]+=$6;d7[$1]+=$8;n[$1]+=1}END{for (d in d5) print d,d5[d]/n[d],d7[d]/n[d]}' FS="[-\t]" ff
05/13/12 13.2694 13.171
05/02/12 15.9193 14.4067
05/18/12 20.0554 17.0706
05/19/12 15.5003 13.9559
05/15/12 15.6814 13.6885
05/16/12 19.4222 17.1549

# 12  
Old 11-01-2012
Yes that solution will only work if the time stamps are in the right order, which appears to be the case with the input sample that the OP posted...
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